(x^2+x-5)/x+3x/(x^2+x-5)+4=0

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Solution for (x^2+x-5)/x+3x/(x^2+x-5)+4=0 equation: 



(x^2+x-5)/x+3x/(x^2+x-5)+4=0



Domain of the equation: x!=0

x∈R





Domain of the equation: (x^2+x-5)!=0

We move all terms containing x to the left, all other terms to the right

x^2+x!=5

x∈R



We calculate fractions

We do not support expression: x^3

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